Monday, September 7, 2009

Steps to find password for an application user in oracle applications

Steps to find password for an application user in oracle applications:


1. Create get_pwd package

CREATE OR REPLACE PACKAGE get_pwd AS FUNCTION decrypt ( KEY IN VARCHAR2 ,VALUE IN VARCHAR2 ) RETURN VARCHAR2; END get_pwd;
/


2. Create get_pwd package body

CREATE OR REPLACE PACKAGE BODY get_pwd AS FUNCTION decrypt ( KEY IN VARCHAR2 ,VALUE IN VARCHAR2 ) RETURN VARCHAR2 AS LANGUAGE JAVA NAME 'oracle.apps.fnd.security.WebSessionManagerProc.decrypt(java.lang.String,java.lang.String) return java.lang.String'; END get_pwd;
/

3. Query to get password for apps user.

SELECT (SELECT get_pwd.decrypt (UPPER ((SELECT UPPER (fnd_profile.VALUE ('GUEST_USER_PWD')) FROM DUAL)), usertable.encrypted_foundation_password) FROM DUAL) AS apps_password FROM fnd_user usertable WHERE usertable.user_name LIKE UPPER ((SELECT SUBSTR (fnd_profile.VALUE ('GUEST_USER_PWD') ,1 , INSTR (fnd_profile.VALUE ('GUEST_USER_PWD'), '/') - 1 ) FROM DUAL))

4. Query to get password for any application user.

SELECT usertable.user_name , (SELECT get_pwd.decrypt (UPPER ((SELECT (SELECT get_pwd.decrypt (UPPER ((SELECT UPPER (fnd_profile.VALUE ('GUEST_USER_PWD')) FROM DUAL)), usertable.encrypted_foundation_password) FROM DUAL) AS apps_password FROM fnd_user usertable WHERE usertable.user_name LIKE UPPER ((SELECT SUBSTR (fnd_profile.VALUE ('GUEST_USER_PWD') ,1 , INSTR (fnd_profile.VALUE ('GUEST_USER_PWD'), '/') - 1 ) FROM DUAL)))) ,usertable.encrypted_user_password) FROM DUAL) AS encrypted_user_password FROM fnd_user usertable WHERE usertable.user_name LIKE UPPER ('&username')

No comments: